BountiesBy Marian MendezPage 2 of 2

SOLUTION TO BOUNTIES : ROJ BLAKE is worth 126 Credits. Following is a detailed explanation of one method of solving this puzzle. BELKOV(101)  BEK(49) = LOV(52) AVALON(111)  AVON(63) = AL(48) KERR AVON(104)  AVON(63) = KERR(41) KERRILL(112)  KERR(41) = ILL(71) ANNA(72) = (2 times AN)(72) So by dividing by 2 we find that AN(36) AVON(63)  AN(36) = VO(27) VILA(78)  AL(48) = VI(30) LOV(52)  VO(27) = L(25) ILL(71)  L(25)L(25) = I(21) AL(48)  L(25) = A(23) VI(30)  I(21) = V(9) VO(27)  V(9) = O(18) AN(36)  A(23) = N(13) TARRANT(95)  A(23)A(23)N(13) = TRRT(36) TRRT(36) = (2 times TR)(36) So by dividing by 2 we find that TR(18) ARLEN(82)  N(13) = ARLE(69) LIBERATOR(146)  ARLE(69) =IBTOR(77) IBTOR(77)  I(21)O(18) = BTR(38) BTR(38)  TR(18) = B(20) ARLEN(82)  A(23)L(25)N(13) = RE(21) KERR(41)  RE(21) = KR(20) Since RE(21) and KR(20) Then E = K +1 JENNA(69)  N(13)N(13)A(23) = JE(20) Since RE(21) and JE(20) Then R = J +1 BEK(49)  B(20) = EK(29) Since E = K + 1 Then subtracting 1 from 29 and dividing by 2 will give K(14) Since E = K + 1 Then E(15) JE(20)  E(15) = J(5) Since R = J + 1 Then R(6) R(6) + O(18) + J(5) + B(20)+ L(25) + A(23) + K(14) + E(15) =ROJ BLAKE(126) (Did you notice that we had no use for Bayban? Vila would agree with that.) 