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Bounties

By Marian Mendez
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SOLUTION TO BOUNTIES : ROJ BLAKE is worth 126 Credits.

Following is a detailed explanation of one method of solving this puzzle.

BELKOV(101) - BEK(49) = LOV(52)

AVALON(111) - AVON(63) = AL(48)

KERR AVON(104) - AVON(63) = KERR(41)

KERRILL(112) - KERR(41) = ILL(71)

ANNA(72) = (2 times AN)(72)

So by dividing by 2 we find that AN(36)

AVON(63) - AN(36) = VO(27)

VILA(78) - AL(48) = VI(30)

LOV(52) - VO(27) = L(25)

ILL(71) - L(25)L(25) = I(21)

AL(48) - L(25) = A(23)

VI(30) - I(21) = V(9)

VO(27) - V(9) = O(18)

AN(36) - A(23) = N(13)

TARRANT(95) - A(23)A(23)N(13) = TRRT(36)

TRRT(36) = (2 times TR)(36)

So by dividing by 2 we find that TR(18)

ARLEN(82) - N(13) = ARLE(69)

LIBERATOR(146) - ARLE(69) =IBTOR(77)

IBTOR(77) - I(21)O(18) = BTR(38)

BTR(38) - TR(18) = B(20)

ARLEN(82) - A(23)L(25)N(13) = RE(21)

KERR(41) - RE(21) = KR(20)

Since RE(21) and KR(20) Then E = K +1

JENNA(69) - N(13)N(13)A(23) = JE(20)

Since RE(21) and JE(20) Then R = J +1

BEK(49) - B(20) = EK(29)

Since E = K + 1 Then subtracting 1 from 29 and dividing by 2 will give K(14) Since E = K + 1 Then E(15)

JE(20) - E(15) = J(5)

Since R = J + 1 Then R(6)

R(6) + O(18) + J(5) + B(20)+ L(25) + A(23) + K(14) + E(15) =ROJ BLAKE(126)

(Did you notice that we had no use for Bayban? Vila would agree with that.)


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